y^2=2y-4

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Solution for y^2=2y-4 equation:


Simplifying
y2 = 2y + -4

Reorder the terms:
y2 = -4 + 2y

Solving
y2 = -4 + 2y

Solving for variable 'y'.

Reorder the terms:
4 + -2y + y2 = -4 + 2y + 4 + -2y

Reorder the terms:
4 + -2y + y2 = -4 + 4 + 2y + -2y

Combine like terms: -4 + 4 = 0
4 + -2y + y2 = 0 + 2y + -2y
4 + -2y + y2 = 2y + -2y

Combine like terms: 2y + -2y = 0
4 + -2y + y2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-4' to each side of the equation.
4 + -2y + -4 + y2 = 0 + -4

Reorder the terms:
4 + -4 + -2y + y2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -2y + y2 = 0 + -4
-2y + y2 = 0 + -4

Combine like terms: 0 + -4 = -4
-2y + y2 = -4

The y term is -2y.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2y + 1 + y2 = -4 + 1

Reorder the terms:
1 + -2y + y2 = -4 + 1

Combine like terms: -4 + 1 = -3
1 + -2y + y2 = -3

Factor a perfect square on the left side:
(y + -1)(y + -1) = -3

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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